document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=199280>Question 199280</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The president of a company is forming a committee. He must choose 8 people out of his 42 employees to be on this committee. How many combinations are possible? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #149766 by </B><A HREF=/tutors/aboutme.mpl?userid=tutorvolunteer><B>tutorvolunteer(9)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=tutorvolunteer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=149766\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Since it is a combination (not a permutation, since order doesn't matter - person A can be paired with person B, and it is no different than person B being paired with person A) use the \"combination\" function on your graphing calculator.\r<BR>\n" );
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document.write( "8 Choose 42  (simplify using a graphing calc)\r<BR>\n" );
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document.write( "Or, you can visit this website for the formula http://www.mathsisfun.com/combinatorics/combinations-permutations.html </SPAN>\n" );
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