document.write( "Question 199293: Factor each polynomial by splitting the middle term and grouping
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\n" ); document.write( "6x squared plus x minus 12 = the answer should be (2x plus 3)(3X MINUS 4)
\n" ); document.write( "but I can't seem to get it there/ please help/thanks \n" ); document.write( "
Algebra.Com's Answer #149752 by checkley77(12844)\"\" \"About 
You can put this solution on YOUR website!
6x^2+x-12
\n" ); document.write( "The factors of 6 are (1 & 6), (-1 & -6), (2 & 3), (-2 &-3).
\n" ); document.write( "The factors of 12 are (-1 & 12), (1 & -12), (-2 & 6), (2 & -6), (-3 & 4),
\n" ); document.write( "(3 & -4).
\n" ); document.write( "Now you need to select a set from each term that when multiplied together will equal +1, the middle term.
\n" ); document.write( "Examples:
\n" ); document.write( "Use the (1,6) & (-1,12)
\n" ); document.write( "(1*-1)+(6*12)=-1*72=71 not close.
\n" ); document.write( "Use the (2,3) & (-2,6)
\n" ); document.write( "(2*-2)+(3*6)=-4+18=14 closer.
\n" ); document.write( "Use the (2,3) & (-4,3)
\n" ); document.write( "(2*-4)+(3*3)=-8+9=1 looks like a winner.
\n" ); document.write( "Thus we have: (2x+3)(3x-4)using FOIL we get.
\n" ); document.write( "2x*3x=6x^2
\n" ); document.write( "2x*-4=-8x
\n" ); document.write( "3*3x=9x
\n" ); document.write( "3*-4=-12
\n" ); document.write( "6x^2-8x+9x-12
\n" ); document.write( "6x^2+x-12\r
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