document.write( "Question 199298This question is from textbook
\n" ); document.write( ": prove each identity, SHOW WORK\r
\n" ); document.write( "\n" ); document.write( "a. cos(2(3.14)-A)=cos A\r
\n" ); document.write( "\n" ); document.write( "b. sin((3(3.14)/2)-A)=-cosA\r
\n" ); document.write( "\n" ); document.write( "c. use the identity for sin(A+B) to prove the identity sin2A=2sinAcosA\r
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Algebra.Com's Answer #149750 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
I'll do the first one to get you started. Note: I'll use \"pi\" for 3.14\r
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\n" ); document.write( "\n" ); document.write( "\"cos%282pi-A%29=cos%28A%29\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"cos%282pi%29cos%28A%29%2Bsin%282pi%29sin%28A%29=cos%28A%29\" Expand\r
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\n" ); document.write( "\n" ); document.write( "\"%281%29cos%28A%29%2B%280%29sin%28A%29=cos%28A%29\" Evaluate the cosine of \"2pi\" to get 1. Evaluate the sine of \"2pi\" to get 0\r
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\n" ); document.write( "\n" ); document.write( "\"cos%28A%29%2B0=cos%28A%29\" Multiply\r
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\n" ); document.write( "\n" ); document.write( "\"cos%28A%29=cos%28A%29\" Simplify\r
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\n" ); document.write( "\n" ); document.write( "So this verifies the identity.
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