document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=199293>Question 199293</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Factor each polynomial by splitting the middle term and grouping<BR>\n" );
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document.write( "6x squared plus x minus 12 =     the answer should be (2x plus 3)(3X MINUS 4)<BR>\n" );
document.write( "but I can't seem to get it there/ please help/thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #149747 by </B><A HREF=/tutors/aboutme.mpl?userid=rfer><B>rfer(16322)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rfer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=149747\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> multiply the factored form.<BR>\n" );
document.write( "(2x+3)(3x-4)= 6x^2+x-12<BR>\n" );
document.write( "take (2x)(3x)=6x^2<BR>\n" );
document.write( "(2x)(-4)+(3)(3x)=x<BR>\n" );
document.write( "(3)(-4)=-12 </SPAN>\n" );
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