document.write( "Question 199256: Draw a isosceles triangle ACB which is inscribed in a semicircle with a diameter of length 32.Find the area of the shaded region in terms of pie.(the shaded region is the circle) \n" ); document.write( "

Algebra.Com's Answer #149740 by RAY100(1637) $\"\"$ $\"About$

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Remember that a triangle inscribed in a semicircle is a rt triangle,,,,therefore we have a rt isosceles triangle ,,,with hypotenuse = 32.
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\n" ); document.write( "since the ratio of sides are 1 :1:sqrt2 ,,,, 32 / sqrt2 = s / 1,,, or s= 22.627,,,(16 sqrt2)
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\n" ); document.write( "Area of triangle = 1/2 *b *h = 1/2 * 22.627 *22.627 = 256
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\n" ); document.write( "Area of semi circle = 1/2 * pi * r^2 = 1/2 * pi * 16^2 = 128 * pi
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\n" ); document.write( "Area of shaded area between is ( 128 pi - 256) = 128 (pi-2) \n" ); document.write( "

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