document.write( "Question 199224: The diagonal of a rectabgle is 8cm. The length of the rectangle is 1.6cm more than the width. Find the dimensions
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #149735 by checkley77(12844)\"\" \"About 
You can put this solution on YOUR website!
x^2+(x+1.6)^2=8^2
\n" ); document.write( "x^2+x^2+3.2x+2.56=64
\n" ); document.write( "2x^2+3.2x+2.56-64=0
\n" ); document.write( "2x^2+3.2x-61.44=0
\n" ); document.write( "2(x^2+1.6x-30.72)=0
\n" ); document.write( "(x-4.8)(x+6.4)=0
\n" ); document.write( "x-4.8=0
\n" ); document.write( "x=4.8 ans. for the width of the rectangle.
\n" ); document.write( "4.8+1.6=6.4 ans. for the length.
\n" ); document.write( "
\n" ); document.write( "
\n" );