document.write( "Question 199246: 4) Solve. (n over n-4/9) -(n over n+4/9)= (1 over n)\r
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Algebra.Com's Answer #149720 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"n%2F%28n-4%2F9%29-n%2F%28n%2B4%2F9%29=1%2Fn\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"n%2F%28%281%2F9%29%289n-4%29%29-n%2F%28%281%2F9%29%289n%2B4%29%29=1%2Fn\" Factor out \"1%2F9\" (to make the inside terms have whole numbers)\r
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\n" ); document.write( "\n" ); document.write( "\"%289n%29%2F%289n-4%29-%289n%29%2F%289n%2B4%29=1%2Fn\" Multiply both the numerator and denominator by the reciprocal of \"1%2F9\"\r
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\n" ); document.write( "\n" ); document.write( " Multiply every term on both sides by the LCD \"n%289n-4%29%289n%2B4%29\". Doing this will eliminate all of the fractions.\r
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\n" ); document.write( "\n" ); document.write( "\"n%289n%2B4%29%289n%29-n%289n-4%29%289n%29=%289n-4%29%289n%2B4%29\" Simplify\r
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\n" ); document.write( "\n" ); document.write( "\"9n%2An%289n%2B4%29-9n%2An%289n-4%29=%289n-4%29%289n%2B4%29\" Rearrange the terms.\r
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\n" ); document.write( "\n" ); document.write( "\"9n%5E2%289n%2B4%29-9n%5E2%289n-4%29=%289n-4%29%289n%2B4%29\" Multiply\r
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\n" ); document.write( "\n" ); document.write( "\"81n%5E3%2B36n%5E2-81n%5E3%2B36n%5E2=%289n-4%29%289n%2B4%29\" Distribute\r
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\n" ); document.write( "\n" ); document.write( "\"72n%5E2=%289n-4%29%289n%2B4%29\" Combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "\"72n%5E2=81n%5E2-16\" FOIL\r
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\n" ); document.write( "\n" ); document.write( "\"72n%5E2-81n%5E2=-16\" Subtract \"81n%5E2\" from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"-9n%5E2=-16\" Combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "\"n%5E2=-16%2F%28-9%29\" Divide both sides by -9.\r
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\n" ); document.write( "\n" ); document.write( "\"n%5E2=16%2F9\" Reduce\r
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\n" ); document.write( "\n" ); document.write( "\"n=%22%22%2B-sqrt%2816%2F9%29\" Take the square root of both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"n=sqrt%2816%2F9%29\" or \"n=-sqrt%2816%2F9%29\" Break up the \"plus/minus\"\r
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\n" ); document.write( "\n" ); document.write( "\"n=4%2F3\" or \"n=-4%2F3\" Take the square root of \"16%2F9\" to get \"4%2F3\"\r
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\n" ); document.write( "\n" ); document.write( "So the solutions are \"n=4%2F3\" or \"n=-4%2F3\"\r
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