document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=199231>Question 199231</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Given triangle ABC with b=6 c=9 and A=146, what is the length of a? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #149699 by </B><A HREF=/tutors/aboutme.mpl?userid=RAY100><B>RAY100(1637)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=RAY100><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=149699\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> as  we  know  two  adjacent  sides  and  included  angle,  we  can  find  remaining  side  using<BR>\n" );
document.write( "law  of  cosines<BR>\n" );
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document.write( "a^2 = b^2 + c^2 - 2 bc  cos  theta<BR>\n" );
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document.write( "a^2 = 6^2 + 9^2 - 2 * 6 * 9 *cos  146<BR>\n" );
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document.write( "a^2 = 36 +81 + 89.536 = 206.54<BR>\n" );
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document.write( "a= 14.37<BR>\n" );
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document.write( "checking  using  law  of  sines<BR>\n" );
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document.write( "14.37/sin 146 =  25.700 =  6 / sin B  = 9 / sin C<BR>\n" );
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document.write( "sin B = 6 / 25.7 =.2335 ,,,, B=13.5 deg<BR>\n" );
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document.write( "sin C = 9/25.7 =.3502 ,,,,C = 20.5  deg<BR>\n" );
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document.write( "A + B + C = 146 +13.5 + 20.5 = 180,,,,ok </SPAN>\n" );
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