document.write( "Question 199233: Two angles are complementary. The sum of the measure of the first angle and the one-fourth the second angel is 75º. Find the measures of the angles.\r
\n" ); document.write( "\n" ); document.write( "I know that two angles have to equal 90º. So do I take 1/4 of 75º = 18.75. 90-18.75 = 71.25. Would the angles be 75º, 18.75º & 71.25º?
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Algebra.Com's Answer #149694 by Earlsdon(6294)\"\" \"About 
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Let x be the first angle, then (90-x) is the measure of the second angle, because the sum of these two complementary angles is 90 degrees.
\n" ); document.write( "\"x%2B%2890-x%29+=+90\"
\n" ); document.write( "The problem states that the sum of the first angle (x) and one fourth of the second angle (\"%281%2F4%29%2890-x%29\") is 75 degrees, so you can write the equation to find x.
\n" ); document.write( "\"x%2B%281%2F4%29%2890-x%29+=+75\" Multiply through by 4 to clear the fraction.
\n" ); document.write( "\"4x%2B%2890-x%29+=+300\" Simplfy the left side.
\n" ); document.write( "\"3x%2B90+=+300\" Subtract 90 from both sides.
\n" ); document.write( "\"3x+=+210\" Finally, divide both sides by 3.
\n" ); document.write( "\"x+=+70\"degrees, and...
\n" ); document.write( "\"90-x+=+20\"degrees.
\n" ); document.write( "Check:
\n" ); document.write( "\"x%2B%281%2F4%29%2890-x%29+=+75\" Substitute x = 70.
\n" ); document.write( "\"70%2B%281%2F4%29%2890-70%29+=+75\"
\n" ); document.write( "\"70%2B%281%2F4%29%2820%29+=+75\"
\n" ); document.write( "\"70%2B5+=+75\"
\n" ); document.write( "\"75+=+75\"
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