document.write( "Question 199219: A jar contains a total of 85 coins, all of which are either DIMES OR QUARTERS. If the coins together are worth $15.40, how many of each type of coin are in the jar?\r
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\n" ); document.write( "\n" ); document.write( "Please help -- can't figure this one out.\r
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Algebra.Com's Answer #149691 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
A jar contains a total of 85 coins, all of which are either DIMES OR QUARTERS.
\n" ); document.write( " If the coins together are worth $15.40, how many of each type of coin are in the jar?
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\n" ); document.write( "Let d = number of dimes
\n" ); document.write( "Let q = number of quarters
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\n" ); document.write( "It says,\"A jar contains a total of 85 coins,\"; therefore:
\n" ); document.write( "d + q = 85
\n" ); document.write( "or
\n" ); document.write( "d = (85-q); use for substitution
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\n" ); document.write( "\"If the coins together are worth $15.40,\"; therefore:
\n" ); document.write( ".10d + .25q = 15.40
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\n" ); document.write( "Substitute (85-q) for d in the above equation
\n" ); document.write( ".10(85-q) + .25q = 15.40
\n" ); document.write( "8.5 - .10q + .25q = 15.40
\n" ); document.write( "-.10q + .25q = 15.40 - 8.5
\n" ); document.write( ".15q = 6.90
\n" ); document.write( "q = \"6.9%2F.15\"
\n" ); document.write( "q = 46 quarters
\n" ); document.write( "then
\n" ); document.write( "d = 85 - 46
\n" ); document.write( "d = 39 dimes
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\n" ); document.write( "Check solution, find the values
\n" ); document.write( ".10(39) + .25(46) =
\n" ); document.write( "3.90 + 11.50 = 15.40\r
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