document.write( "Question 199163: There are only three flavors of gumdrops in a jar containing 40 gumdrops. There are 3 times as many cherry gumdrops as lemon gumdrops. There are 4 more than twice as many orange gumdrops as lemon gumdrops.
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document.write( "a)How many gumdrops of each flavor are there in the jar?(only an algebraic solution will be accepted.)
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document.write( "b)Two gumdrops are drawn at random without replacement.Find the probability that both are the same flavor. \n" );
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Algebra.Com's Answer #149640 by rfer(16322)![]() ![]() ![]() You can put this solution on YOUR website! Big problem. \n" ); document.write( "3 flavors, 40 total \n" ); document.write( "L=lemon, C=cherry, O=orange \n" ); document.write( "L=X, C=X(3), O=X(2)+4 \n" ); document.write( "X+3X+(2X+4)=total \n" ); document.write( "6X+4=40 \n" ); document.write( "6X=40-4 \n" ); document.write( "6X=36 \n" ); document.write( "X=6 \n" ); document.write( "Therefore lemon=6, cherry=18, orange=16 ,=40 total\r \n" ); document.write( "\n" ); document.write( "b) \n" ); document.write( "first draw \n" ); document.write( "lemon, 6/40 or 15%; cherry, 18/40 or 45%; orange, 16/40 or 40% \n" ); document.write( "second draw \n" ); document.write( "lemon, 5/39 or 13%; cherry, 17/39 or 44%; orange, 15/39 or 38% \n" ); document.write( "sumation \n" ); document.write( "draw the same twice \n" ); document.write( "lemon, 2% chance; cherry, 20% chance; orange, 15% chance\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |