document.write( "Question 199148: Find three consecutive positive even integers such that the product of the first and second is two less than five times the third.(Only an algebraic solution will be accepted.): Find three consecutive positive even integers such that the product of the first and second is two less than five times the third.(Only an algebraic solution will be accepted.)
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Algebra.Com's Answer #149624 by checkley75(3666)\"\" \"About 
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Let x, x+2 & x+4 be the 3 even integers.
\n" ); document.write( "x(x+2)=5(x+4)-2
\n" ); document.write( "x^2+2x=5x+20-2
\n" ); document.write( "x^2+2x-5x-18=0
\n" ); document.write( "x^2-3x-18=0
\n" ); document.write( "(x-6)(x+3)=0
\n" ); document.write( "x-6=0
\n" ); document.write( "x=6 ans. for the first even integer.
\n" ); document.write( "6+2=8 for the second even integer.
\n" ); document.write( "6+4=10 for the third even integer.
\n" ); document.write( "Proof:
\n" ); document.write( "6*8=5*10-2
\n" ); document.write( "48=50-2
\n" ); document.write( "48=48
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