document.write( "Question 199130: the perimeter of certain rectangule is16 timesthe width. the lengthis 12cm. more than the width. find the widthodf the rectangule \n" ); document.write( "
Algebra.Com's Answer #149606 by nerdybill(7384) You can put this solution on YOUR website! the perimeter of certain rectangule is16 timesthe width. the lengthis 12cm. more than the width. find the widthodf the rectangule \n" ); document.write( ". \n" ); document.write( "Let w = width of the rectangle \n" ); document.write( "then \n" ); document.write( "w+12 = length of the rectangle \n" ); document.write( ". \n" ); document.write( "perimeter = 2(width + length) \n" ); document.write( "16w = 2(w + w+12) \n" ); document.write( "16w = 2(2w+12) \n" ); document.write( "16w = 4w+24 \n" ); document.write( "12w = 24 \n" ); document.write( "w = 2 cm (width) \n" ); document.write( " \n" ); document.write( " |