document.write( "Question 199099This question is from textbook Intermediate Algebra An Applied Approach
\n" ); document.write( ": The larger of two printers being used to print the payroll for a major corporation requires 30 min to print the payroll. After both printers have been operating for 10 min, the larger printer malfunctions. The smaller printer requires 40 more minutes to complete the payroll. How long would it take the smaller printer working alone to print the payroll? \n" ); document.write( "
Algebra.Com's Answer #149576 by ankor@dixie-net.com(22740)\"\" \"About 
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The larger of two printers being used to print the payroll for a major
\n" ); document.write( " corporation requires 30 min to print the payroll. After both printers have
\n" ); document.write( " been operating for 10 min, the larger printer malfunctions.
\n" ); document.write( "The smaller printer requires 40 more minutes to complete the payroll.
\n" ); document.write( "How long would it take the smaller printer working alone to print the payroll?
\n" ); document.write( ":
\n" ); document.write( "Let x = time (in minutes) required by the small printer working alone
\n" ); document.write( "Let the completed job = 1
\n" ); document.write( ":
\n" ); document.write( "Smaller printer will operate for 10 + 40 = 50 min
\n" ); document.write( ":
\n" ); document.write( "\"10%2F30\" + \"50%2Fx\" = 1
\n" ); document.write( ":
\n" ); document.write( "Multiply equation by 30x, results
\n" ); document.write( "10x + 30(50) = 30x
\n" ); document.write( "1500 = 30x - 10x
\n" ); document.write( "1500 = 20x
\n" ); document.write( "x = \"1500%2F20\"
\n" ); document.write( "x = 75 min, small printer alone
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check solution:
\n" ); document.write( "10/30 + 50/75 =
\n" ); document.write( "1/3 + 2/3 = 1\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
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