document.write( "Question 199079: 2. An express train and a local train both leave Gray’s Lake at 12:00 noon and head for Chicago 60 miles away. The express travels twice as fast as the local and arrives 2 hours ahead of it. Find the speed of each train. \r
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\n" ); document.write( "\n" ); document.write( "I am confused by this problem and do not know where to start.
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Algebra.Com's Answer #149533 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Let \"t%5B1%5D\" = time of express train and \"t%5B2%5D\" = time of local train\r
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\n" ); document.write( "\n" ); document.write( "Also, let \"r%5B1%5D\" = speed of express train and \"r%5B2%5D\" = speed of local train\r
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\n" ); document.write( "\n" ); document.write( "Since the \"express train travels twice as fast as the local train\", this means that \"r%5B1%5D=2%2Ar%5B2%5D\"\r
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\n" ); document.write( "\n" ); document.write( "Also, because \"the express train arrives 2 hours ahead of the local train\", this tells us \"t%5B1%5D=t%5B2%5D-2\"\r
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\n" ); document.write( "\n" ); document.write( "Now let's set up the formula for the local train:\r
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\n" ); document.write( "\n" ); document.write( "\"d=rt\" Start with the distance rate time formula\r
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\n" ); document.write( "\n" ); document.write( "\"60=r%5B2%5D%2At%5B2%5D\" Plug in \"d=60\", \"r=r%5B2%5D\" and \"t=t%5B2%5D\"\r
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\n" ); document.write( "\n" ); document.write( "\"60%2Ft%5B2%5D=r%5B2%5D\" Divide both sides by \"t%5B2%5D\".\r
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\n" ); document.write( "\n" ); document.write( "So after isolating the second speed, we get \"r%5B2%5D=60%2Ft%5B2%5D\"\r
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\n" ); document.write( "\n" ); document.write( "Now let's set up the formula for the express train:\r
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\n" ); document.write( "\n" ); document.write( "\"d=rt\" Start with the distance rate time formula\r
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\n" ); document.write( "\n" ); document.write( "\"60=r%5B1%5D%2At%5B1%5D\" Plug in \"d=60\", \"r=r%5B1%5D\" and \"t=t%5B1%5D\"\r
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\n" ); document.write( "\n" ); document.write( "\"60=%282%2Ar%5B2%5D%29%2A%28t%5B2%5D-2%29\" Plug in \"r%5B1%5D=2%2Ar%5B2%5D\" and \"t%5B1%5D=t%5B2%5D-2\"\r
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\n" ); document.write( "\n" ); document.write( "\"60=%282%2A%2860%2Ft%5B2%5D%29%29%2A%28t%5B2%5D-2%29\" Plug in \"r%5B2%5D=60%2Ft%5B2%5D\"\r
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\n" ); document.write( "\n" ); document.write( "\"60=%28120%2Ft%5B2%5D%29%2A%28t%5B2%5D-2%29\" Multiply\r
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\n" ); document.write( "\n" ); document.write( "\"60t%5B2%5D=120%28t%5B2%5D-2%29\" Multiply both sides by \"t%5B2%5D\".\r
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\n" ); document.write( "\n" ); document.write( "\"60t%5B2%5D=120t%5B2%5D-240\" Distribute\r
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\n" ); document.write( "\n" ); document.write( "\"60t%5B2%5D-120t%5B2%5D=-240\" Subtract \"120t%5B2%5D\" from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"-60t%5B2%5D=-240\" Combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "\"t%5B2%5D=-240%2F%28-60%29\" Divide both sides by -60 to isolate \"t%5B2%5D\".\r
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\n" ); document.write( "\n" ); document.write( "\"t%5B2%5D=4\" Divide\r
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\n" ); document.write( "\n" ); document.write( "So it takes 4 hours for the local train\r
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\n" ); document.write( "\n" ); document.write( "\"60=r%5B2%5D%2At%5B2%5D\" Go back to the local train formula\r
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\n" ); document.write( "\n" ); document.write( "\"60=r%5B2%5D%2A4\" Plug in \"t%5B2%5D=4\"\r
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\n" ); document.write( "\n" ); document.write( "\"60%2F4=r%5B2%5D\" Divide both sides by 4.\r
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\n" ); document.write( "\n" ); document.write( "\"15=r%5B2%5D\" Divide.\r
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\n" ); document.write( "\n" ); document.write( "So the speed of the local train is 15 mph\r
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\n" ); document.write( "\n" ); document.write( "Now simply double the speed of the local train to get \"15%2A2=30\"\r
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\n" ); document.write( "\n" ); document.write( "So the speed of the local train is 15 mph and the speed of the express train is 30 mph. \r
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\n" ); document.write( "\n" ); document.write( "Note: nowhere in the solution above is a mention of 12:00 noon. This information is unnecessary and it is put in there to throw you off.
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