document.write( "Question 199007: A parabolic arch has a span of 120 feet and a maximum height of 25 feet. Choose a suitable rectangular coordinate system and find the equation of the parabola. Then calculate the height of the arch 10, 20 and 40 feet from the center. Provide a sketch representing the situation and be sure it is clearly labeled with coordinates. \n" ); document.write( "
Algebra.Com's Answer #149528 by ankor@dixie-net.com(22740)\"\" \"About 
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A parabolic arch has a span of 120 feet and a maximum height of 25 feet.
\n" ); document.write( " Choose a suitable rectangular coordinate system and find the equation of the
\n" ); document.write( " parabola. Then calculate the height of the arch 10, 20 and 40 feet from the center.
\n" ); document.write( ":
\n" ); document.write( "Find the equation using the format y = ax^2 + bx + c (c=0, we can ignore that)
\n" ); document.write( ":
\n" ); document.write( "Using the vertex
\n" ); document.write( "x=60, y = 25
\n" ); document.write( "a(60^2) + 60b = 25
\n" ); document.write( "3600a + 60b = 25
\n" ); document.write( ":
\n" ); document.write( "Using the x intercept
\n" ); document.write( "x=120, y=0
\n" ); document.write( "a(120^2) + 120b = 0
\n" ); document.write( "14400a + 120b = 0
\n" ); document.write( ":
\n" ); document.write( "Multiply the 1st equation by 2, subtract from the 2nd equation
\n" ); document.write( "14400a + 120b = 0
\n" ); document.write( " 7200a + 120b = 25
\n" ); document.write( "--------------------subtraction eliminates b, find a
\n" ); document.write( "7200a = -25
\n" ); document.write( "a = \"-25%2F7200\"
\n" ); document.write( "a = -.00694
\n" ); document.write( ":
\n" ); document.write( "Find b using the 2nd equation, substitute -.00694 for a
\n" ); document.write( "14400(-.00964) + 120b = 0
\n" ); document.write( "-100 + 120b = 0
\n" ); document.write( "120b = 100
\n" ); document.write( "b = \"100%2F120\"
\n" ); document.write( "b = .833
\n" ); document.write( ":
\n" ); document.write( "y = -.00694x^2 + .8333x; the equation for this parabola
\n" ); document.write( ":
\n" ); document.write( "10 ft from center: 60-10 = 50 = x
\n" ); document.write( "y = -.00694(50^2) + .8333(50)
\n" ); document.write( "y = -17.35 + 41.665
\n" ); document.write( "y = 24.3 ft high, 10 ft from center
\n" ); document.write( ":
\n" ); document.write( "20 ft from center: 60-20 = 40 = x
\n" ); document.write( "y = -.00694(40^2) + .8333(40)
\n" ); document.write( "y = -11.1 + 33.3
\n" ); document.write( "y = 22.2 ft high. 20 ft from center
\n" ); document.write( ":
\n" ); document.write( "40 ft from center: 60-40 = 20 = x
\n" ); document.write( "y = -.00694(20^2) + .8333(20)
\n" ); document.write( "y = -2.8 + 16.7
\n" ); document.write( "y = 13.9 ft high. 40 ft from center
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "The graph of this equation:
\n" ); document.write( "\"+graph%28+300%2C+200%2C+-10%2C+130%2C+-10%2C+30%2C+-.00694x%5E2%2B.833x%29+\"
\n" ); document.write( ":
\n" ); document.write( " Provide a sketch representing the situation and be sure it is clearly labeled with coordinates.\r
\n" ); document.write( "\n" ); document.write( "Your sketch should resemble this graph, you should be able to label this now
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