document.write( "Question 198981: The distance between two cities is ninety miles, and a woman drives from one city to the other at a rate of forty-five mph. At what rate must she return if the total travel time is three hours and forty minutes? \n" ); document.write( "
Algebra.Com's Answer #149523 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! The distance between two cities is ninety miles, and a woman drives from one \n" ); document.write( " city to the other at a rate of forty-five mph. \n" ); document.write( " At what rate must she return if the total travel time is three hours and forty minutes? \n" ); document.write( ": \n" ); document.write( "Let s = speed require to return in 3 hr 40 min \n" ); document.write( ": \n" ); document.write( "Write a time equation: Time = Dist/speed \n" ); document.write( ": \n" ); document.write( "Change time to hrs: 3 & 2/3 hrs = 11/3 hrs \n" ); document.write( ": \n" ); document.write( "To time + return time = 3 hr 40 min \n" ); document.write( " \n" ); document.write( "Multiply equation by 45s \n" ); document.write( "45s* \n" ); document.write( "Cancel denominators, results \n" ); document.write( "90s + 45(90) = 15s(11) \n" ); document.write( "90s + 4050 = 165s \n" ); document.write( "4050 = 165s - 90s \n" ); document.write( "4050 = 75s \n" ); document.write( "s = \n" ); document.write( "s = 54 mph required on the return trip \n" ); document.write( "; \n" ); document.write( ": \n" ); document.write( "Check solution \n" ); document.write( "90/45 + 90/54 = \n" ); document.write( "2 + 1.67 = 3.67 hrs ~ 3 hr 40 min \n" ); document.write( " \n" ); document.write( " |