document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=199039>Question 199039</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/9780495013570/algebrahomeworkh>algebra and trigonometry</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> Two cyclists, 90 mi apart, start riding toward each other at the same time. One cycles twice as fast as the other. If they meet 2h later, at what average speed is each cyclist traveling? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #149511 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley75><B>checkley75(3666)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley75><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=149511\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> D=RT<BR>\n" );
document.write( "90=(X+2X)2<BR>\n" );
document.write( "90=3X*2<BR>\n" );
document.write( "90=6X<BR>\n" );
document.write( "X=90/6<BR>\n" );
document.write( "X=15 MPH FOR THE SLOWER CYCLIST.<BR>\n" );
document.write( "2*15=30 MPH FOR THE FASTER CYCLIST.<BR>\n" );
document.write( "PROOF;<BR>\n" );
document.write( "90=(15+30)2<BR>\n" );
document.write( "90=45*2<BR>\n" );
document.write( "90=90\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );