document.write( "Question 199034: A boat goes 10 miles per hour in still water. It travels 24 miles upstream and 24 miles back in a total of 5 hours. What is the speed of the current? \n" ); document.write( "
Algebra.Com's Answer #149508 by nerdybill(7384)![]() ![]() You can put this solution on YOUR website! A boat goes 10 miles per hour in still water. It travels 24 miles upstream and 24 miles back in a total of 5 hours. What is the speed of the current? \n" ); document.write( ". \n" ); document.write( "Apply the distance formula: \n" ); document.write( "d = rt \n" ); document.write( "where \n" ); document.write( "d is distance \n" ); document.write( "r is rate or speed \n" ); document.write( "t is time \n" ); document.write( ". \n" ); document.write( "Solving for t: \n" ); document.write( "t = d/r \n" ); document.write( ". \n" ); document.write( "Let x = speed of current \n" ); document.write( "then rate or speed: \n" ); document.write( "downstream = 10+x \n" ); document.write( "upstream = 10-x \n" ); document.write( ". \n" ); document.write( "24/(10+x) + 24/(10-x) = 5 \n" ); document.write( "24(10-x) + 24(10+x) = 5(10+x)(10-x) \n" ); document.write( "240-24x + 240+24x = 5(100-10x+10x-x^2) \n" ); document.write( "480 = 500-5x^2 \n" ); document.write( "480+5x^2 = 500 \n" ); document.write( "5x^2 = 20 \n" ); document.write( "x^2 = 4 \n" ); document.write( "x = 2 mph (current)\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |