document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=199013>Question 199013</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If three times a number is increased by 6, the result is 21. The number is<BR>\n" );
document.write( "1)5<BR>\n" );
document.write( "2)9<BR>\n" );
document.write( "3)15<BR>\n" );
document.write( "4)-9 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #149500 by </B><A HREF=/tutors/aboutme.mpl?userid=AbyBavy><B>AbyBavy(4)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=AbyBavy><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=149500\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> To solve this you must first set up an equation. three times a number would be written as 3x. increased by 6 means you are adding six to your 3x. The result is telling you the problem equals 21.\r<BR>\n" );
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document.write( "3x+6=21\r<BR>\n" );
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document.write( "To solve you would first subtract 6 from each side. A possitive 6 minus a negative 6 will cancel out your 6's on the left side. You then do 21-6= 15\r<BR>\n" );
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document.write( "Your problem should now look like this:<BR>\n" );
document.write( "3x=15\r<BR>\n" );
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document.write( "You then divide 3 from both sides. 3x divided by 3 cancells out the 3's so you are left with just x. 15 divided by 3 comes out to be 5. Therefore your answer is #1.\r<BR>\n" );
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document.write( "three times a number is increased by 6, the result is 21. The number is 5.<BR>\n" );
document.write( " </SPAN>\n" );
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