document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=198998>Question 198998</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If n is an integer and 4 is the remainder when 4n - 1 is divided by 5, then n could be </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #149481 by </B><A HREF=/tutors/aboutme.mpl?userid=RAY100><B>RAY100(1637)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=RAY100><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=149481\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x = Quotient  of  above<BR>\n" );
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document.write( "Then 5x+4 = 4n-1,,,,,  that  is  quotient  times divisor is  4 less  than  dividend,,,hence  remainder  4<BR>\n" );
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document.write( " 5x +5 =4n<BR>\n" );
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document.write( "(5x+5) / 4 =n<BR>\n" );
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document.write( "itterate  x  until  n = integer<BR>\n" );
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document.write( "@ x=7,,,n=10<BR>\n" );
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document.write( "check<BR>\n" );
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document.write( "( 4*10 -1) / 5 = 39/5 = 7 rem4 </SPAN>\n" );
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