document.write( "Question 198912: A picture frame dimesions are 20cm by 30cm. If a mat was put inside the frame that decreases the picture area by 264cm^2, how wide is the mat? \n" ); document.write( "
Algebra.Com's Answer #149417 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A picture frame dimensions are 20cm by 30cm. If a mat was put inside the frame \n" ); document.write( " that decreases the picture area by 264cm^2, how wide is the mat? \n" ); document.write( ": \n" ); document.write( "Let x = width of the mat \n" ); document.write( ": \n" ); document.write( "Find the overall area of the picture and frame: \n" ); document.write( "20 * 30 = 600 sq/cm \n" ); document.write( ": \n" ); document.write( "The dimension of the picture inside the mat \n" ); document.write( "(20-2x)by(30-2x) \n" ); document.write( "Foil to find the area: \n" ); document.write( "A = 600 - 100x + 4x^2 \n" ); document.write( ": \n" ); document.write( "Overall area - picture area = 264 sq/cm \n" ); document.write( "600 - (4x^2 - 100x + 600) = 264 \n" ); document.write( ": \n" ); document.write( "Remove the brackets (change signs) arrange as a quadratic eq \n" ); document.write( "-4x^2 + 100x + 600 - 600 - 264 = 0 \n" ); document.write( "-4x^2 + 100x - 264 = 0 \n" ); document.write( "Multiply eq by -1 \n" ); document.write( "4x^2 - 100x + 264 = 0 \n" ); document.write( "Simplify divide by 4 \n" ); document.write( "x^2 - 25x + 66 = 0 \n" ); document.write( "Factor \n" ); document.write( "(x - 22)(x - 3) = 0 \n" ); document.write( "Reasonable solution \n" ); document.write( "x = 3 cm is the width of the mat \n" ); document.write( "; \n" ); document.write( ": \n" ); document.write( "Check solution \n" ); document.write( "Find the area of the picture (2x=6), subtract from the overall dimensions \n" ); document.write( "14 * 24 = 336 \n" ); document.write( "then \n" ); document.write( "600 - 336 = 264; confirms our solution \n" ); document.write( " |