document.write( "Question 198897: Express as a single fraction in simplest form: x over 2 minus x over 3 \n" ); document.write( "
Algebra.Com's Answer #149378 by jim_thompson5910(35256)\"\" \"About 
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\"x%2F2-x%2F3\" Start with the given expression.\r
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\n" ); document.write( "\n" ); document.write( "Take note that the LCD is 6. In order to combine these fractions, we need to get ALL the denominators equal to the LCD.\r
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\n" ); document.write( "\n" ); document.write( "\"%283x%29%2F6-x%2F3\" Multiply both the numerator and denominator of the first fraction by 3 to get the first denominator equal to the LCD 6.\r
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\n" ); document.write( "\n" ); document.write( "\"%283x%29%2F6-%282x%29%2F6\" Multiply both the numerator and denominator of the second fraction by 2 to get the second denominator equal to the LCD 6.\r
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\n" ); document.write( "\n" ); document.write( "\"%283x-2x%29%2F6\" Now that the denominators are equal, we can combine the fractions.\r
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\n" ); document.write( "\n" ); document.write( "\"x%2F6\" Combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "So \"x%2F2-x%2F3=x%2F6\"
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