document.write( "Question 198883: A man travels from Town x to town y at an average rate of 50mph and returns at an average rate of 40pmh. he takes 1/2 hour longer than he would take if he made the round trip at an average of 45 mph. What is the distance from town x to town y. \n" ); document.write( "
Algebra.Com's Answer #149376 by ankor@dixie-net.com(22740)\"\" \"About 
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A man travels from Town x to town y at an average rate of 50mph and returns at
\n" ); document.write( " an average rate of 40pmh. he takes 1/2 hour longer than he would take if he
\n" ); document.write( " made the round trip at an average of 45 mph. What is the distance from town x to town y.
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\n" ); document.write( "Let d = dist of town x to town y
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\n" ); document.write( "Write a time equation: Time = dist/speed
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\n" ); document.write( "To time + return time = 45 mph time + 1/2 hr
\n" ); document.write( "\"d%2F50\" + \"d%2F40\" = \"%282d%29%2F45\" + \"1%2F2\"
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\n" ); document.write( "Multiply equation by 1800:
\n" ); document.write( "1800*\"d%2F50\" + 1800*\"d%2F40\" = 1800*\"%282d%29%2F45\" + 1800*\"1%2F2\"
\n" ); document.write( "Cancel the denominators, results:
\n" ); document.write( "36d + 45d = 40(2d) + 900
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\n" ); document.write( "81d = 80d + 900
\n" ); document.write( "81d - 80d = 900
\n" ); document.write( "d = 900 mi from town x to town y
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\n" ); document.write( "The solution in original time equation (round trip = 1800 mi)
\n" ); document.write( "900/50 + 900/40 = 1800/45 + 1/2
\n" ); document.write( "18 + 22.5 = 40 + .5
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