document.write( "Question 198889: Express 6a²b² divided by 2ab² in lowest terms. \n" ); document.write( "
Algebra.Com's Answer #149369 by jim_thompson5910(35256)\"\" \"About 
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\"%286a%5E2b%5E2%29%2F%282ab%5E2%29\" Start with the given expression.\r
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\n" ); document.write( "\n" ); document.write( "\"%282%2A3%2Aa%2Aa%2Ab%2Ab%29%2F%282%2Aa%2Ab%2Ab%29\" Expand. Remember, \"6a%5E2b%5E2=2%2A3%2Aa%2Aa%2Ab%2Ab\" and \"2ab%5E2=2%2Aa%2Ab%2Ab\"\r
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\n" ); document.write( "\n" ); document.write( " Highlight the common terms.\r
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\n" ); document.write( "\n" ); document.write( " Cancel out the common terms.\r
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\n" ); document.write( "\n" ); document.write( "\"3a\" Simplify.\r
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\n" ); document.write( "\n" ); document.write( "So \"%286a%5E2b%5E2%29%2F%282ab%5E2%29\" simplifies to \"3a\".\r
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\n" ); document.write( "\n" ); document.write( "In other words, \"%286a%5E2b%5E2%29%2F%282ab%5E2%29=3a\" where \"a%3C%3E0\" or \"b%3C%3E0\"
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