document.write( "Question 198867This question is from textbook McDougal Littell Algebra 1
\n" ); document.write( ": Please help me solve by completing the square:\r
\n" ); document.write( "\n" ); document.write( "3x^2-2x-4=0
\n" ); document.write( "

Algebra.Com's Answer #149354 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
First, let's complete the square for \"3x%5E2-2x-4\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"3x%5E2-2x-4\" Start with the left side of the given equation.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"3%28x%5E2-%282%2F3%29x-4%2F3%29\" Factor out the \"x%5E2\" coefficient \"3\". This step is very important: the \"x%5E2\" coefficient must be equal to 1.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Take half of the \"x\" coefficient \"-2%2F3\" to get \"-1%2F3\". In other words, \"%281%2F2%29%28-2%2F3%29=-1%2F3\".\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Now square \"-1%2F3\" to get \"1%2F9\". In other words, \"%28-1%2F3%29%5E2=%28-1%2F3%29%28-1%2F3%29=1%2F9\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"3%28x%5E2-%282%2F3%29x%2Bhighlight%281%2F9-1%2F9%29-4%2F3%29\" Now add and subtract \"1%2F9\" inside the parenthesis. Make sure to place this after the \"x\" term. Notice how \"1%2F9-1%2F9=0\". So the expression is not changed.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"3%28%28x%5E2-%282%2F3%29x%2B1%2F9%29-1%2F9-4%2F3%29\" Group the first three terms.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"3%28%28x-1%2F3%29%5E2-1%2F9-4%2F3%29\" Factor \"x%5E2-%282%2F3%29x%2B1%2F9\" to get \"%28x-1%2F3%29%5E2\".\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"3%28%28x-1%2F3%29%5E2-13%2F9%29\" Combine like terms.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"3%28x-1%2F3%29%5E2%2B3%28-13%2F9%29\" Distribute.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"3%28x-1%2F3%29%5E2-13%2F3\" Multiply.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So after completing the square, \"3x%5E2-2x-4\" transforms to \"3%28x-1%2F3%29%5E2-13%2F3\". So \"3x%5E2-2x-4=3%28x-1%2F3%29%5E2-13%2F3\".\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So \"3x%5E2-2x-4=0\" is equivalent to \"3%28x-1%2F3%29%5E2-13%2F3=0\".\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "----------------------------------------------------------------------\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Now let's solve \"3%28x-1%2F3%29%5E2-13%2F3=0\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"3%28x-1%2F3%29%5E2-13%2F3=0\" Start with the given equation.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"3%28x-1%2F3%29%5E2=0%2B13%2F3\"Add \"13%2F3\" to both sides.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"3%28x-1%2F3%29%5E2=13%2F3\" Combine like terms.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"%28x-1%2F3%29%5E2=%2813%2F3%29%2F%283%29\" Divide both sides by \"3\".\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"%28x-1%2F3%29%5E2=13%2F9\" Reduce.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x-1%2F3=%22%22%2B-sqrt%2813%2F9%29\" Take the square root of both sides.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x-1%2F3=sqrt%2813%2F9%29\" or \"x-1%2F3=-sqrt%2813%2F9%29\" Break up the \"plus/minus\" to form two equations.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x-1%2F3=sqrt%2813%29%2F3\" or \"x-1%2F3=-sqrt%2813%29%2F3\" Simplify the square root.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x=1%2F3%2Bsqrt%2813%29%2F3\" or \"x=1%2F3-sqrt%2813%29%2F3\" Add \"1%2F3\" to both sides.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x=%281%2Bsqrt%2813%29%29%2F%283%29\" or \"x=%281-sqrt%2813%29%29%2F%283%29\" Combine the fractions.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "--------------------------------------\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Answer:\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So the solutions are \"x=%281%2Bsqrt%2813%29%29%2F%283%29\" or \"x=%281-sqrt%2813%29%29%2F%283%29\".
\n" ); document.write( "
\n" );