document.write( "Question 198833: How many mg of a metal containing 45% nickel must be combined with 6 mg of pure nickel to form an alloy containing 78% nickel? \n" ); document.write( "

Algebra.Com's Answer #149339 by josmiceli(19441) $\"\"$ $\"About$

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(mg of nickel) / (mg of alloy) = 78%
\n" ); document.write( "Let $\"x\"$ = mgs of metal with 45% nickel
\n" ); document.write( " $\".45x+%2B+6%29+%2F+%28x+%2B+6%29+=+.78\"$
\n" ); document.write( " $\".45x+%2B+6+=+.78%2A%28x+%2B+6%29\"$
\n" ); document.write( " $\".78x+-+.45x+=+6+-+.78%2A6\"$
\n" ); document.write( " $\".33x+=+1.32\"$
\n" ); document.write( " $\"x+=+4\"$
\n" ); document.write( "4 mg of the metal must be used
\n" ); document.write( "check:
\n" ); document.write( " $\".45x+%2B+6%29+%2F+%28x+%2B+6%29+=+.78\"$
\n" ); document.write( " $\".45%2A4+%2B+6%29+%2F+%284+%2B+6%29+=+.78\"$
\n" ); document.write( " $\"1.8+%2B+6%29+%2F+10+=+.78\"$
\n" ); document.write( " $\"7.8%2F10+=+.78\"$
\n" ); document.write( " $\".78+=+.78\"$
\n" ); document.write( "OK \n" ); document.write( "

\n" );