document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=198806>Question 198806</A>: <I><SPAN STYLE=\"word-break: break-all;\"> from a group of 6 men and 4 women, a committee of 3 is to be selected at random. find P(at least 2 women) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #149337 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=149337\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The probability of selecting a man (m) is .6 and a woman is .4<BR>\n" );
document.write( "the probability of all women is w^3=.4^3=.064<BR>\n" );
document.write( "2/3 being women is 3mw^2=3*.6*.4^2=.288 [the third term of  (m+f)^3].<BR>\n" );
document.write( ".288+.064=.352<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Ed </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );