document.write( "Question 198847This question is from textbook
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document.write( ": Directions state: Find the perimeters and areas of the squares and rectangles in questions 7-10.\r
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document.write( "The figure shown in the text has a picture of a square which is dissected in the middle to form two right triangles. The triangle has two 45 degree and one 90 degree angles. All that is given is six square root of two (6 square root 2) for the hypotenuse of the adjacent right triangles. My apoogies but I do not have a square root symbol key on my computer keyboard. As you can tell I need to solve for the perimeter and area, but I do not even know how to without data given for either side one or side two. \n" );
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Algebra.Com's Answer #149326 by solver91311(24713)![]() ![]() You can put this solution on YOUR website! \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Since it is a square, the triangle formed by two adjacent sides of the square and the diagonal is an isosceles right triangle -- observation confirmed by the fact that you say it is a 90°-45°-45° triangle. All isosceles right triangles are similar, that is to say that their sides are in proportion.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If you have an isosceles right triangle whose legs measure 1 unit, then the Pythagorean Theorem says the hypotenuse is:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "That means that the three sides of any isosceles right triangle are in proportion:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So, if your hypotenuse, i.e. the diagonal of the square, measures \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "is equivalent to\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Can you take it from there?\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "John \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |