document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=27488>Question 27488</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 3(5-a)-4(-1-a) how do i do this problem? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #14931 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=14931\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You have to know the following: a(b+c)=ab+ac<BR>\n" );
document.write( "Also, you have to know (negative)*(negative)=positive<BR>\n" );
document.write( "So you get 15-3a+1+4a<BR>\n" );
document.write( "Now add \"like\" terms, to get:<BR>\n" );
document.write( "a+16<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );