document.write( "Question 198713: Mr. Greene has 8.5 in by 11 in cardboard sheets. As a class project, Mr. Greene asked each of his students to amke an open-top box under these conditions:
\n" );
document.write( "I. Each box must be made by cutting small squares from each corner of a cardboard sheet.
\n" );
document.write( "II. The box must have a volume of 48 in^3
\n" );
document.write( "III. The amount of cardboard waste must be minimized.
\n" );
document.write( "What is the appropriate side length for the small squares that would be cut from the cardboard sheet? \n" );
document.write( "
Algebra.Com's Answer #149271 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Mr. Greene has 8.5 in by 11 in cardboard sheets. As a class project, Mr. Greene \n" ); document.write( " asked each of his students to make an open-top box under these conditions: \n" ); document.write( ": \n" ); document.write( "I. Each box must be made by cutting small squares from each corner of a cardboard sheet. \n" ); document.write( "Let the side of the small square = x \n" ); document.write( "then \n" ); document.write( "the dimension of the box: (8.5-2x) by (11-2x) by x \n" ); document.write( "FOIL \n" ); document.write( "x(93.5 - 17x - 22x +4x^2) \n" ); document.write( "A volume equation \n" ); document.write( "V = 4x^3 - 39x^2 + 93.5x \n" ); document.write( ": \n" ); document.write( "; \n" ); document.write( "II. The box must have a volume of 48 in^3 \n" ); document.write( "4x^3 - 39x^2 + 93.5x = 48 \n" ); document.write( "4x^3 - 39x^2 + 93.5x - 48 = 0 \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "III. The amount of cardboard waste must be minimized. \n" ); document.write( "Graph the above equation to find the values of x: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "What is the appropriate side length for the small squares that would be \n" ); document.write( " cut from the cardboard sheet? \n" ); document.write( ": \n" ); document.write( "The smaller solution: x ~.7\"; would give us the smallest removed squares \n" ); document.write( "; \n" ); document.write( "; \n" ); document.write( ": \n" ); document.write( "Check our solution: 2x = 1.4 \n" ); document.write( "(8.5-1.4) * (11-1.4) * .7 = \n" ); document.write( "7.1 * 9.6 * .7 = 47.4 ~ 48 \n" ); document.write( " |