document.write( "Question 198752: 9 Ibs. of mixed nuts containing 55% peanutes were mixed with 6Ibs of another kind of mixed nuts that contain 40% peanuts. What percent of the new mixture is peanuts? \n" ); document.write( "

Algebra.Com's Answer #149270 by josmiceli(19441) $\"\"$ $\"About$

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In words:
\n" ); document.write( "(lbs of peanuts in final mixture)/(total pounds of mixture) = (% peanuts)
\n" ); document.write( " $\"9%2A.55+=+4.95\"$ lbs
\n" ); document.write( " $\"6%2A.4+=+2.4\"$ lbs
\n" ); document.write( " $\"%284.95+%2B+2.4%29%2F%289+%2B+6%29\"$
\n" ); document.write( " $\"7.35%2F15+=+.49\"$
\n" ); document.write( "The new mixture is 49% peanuts \n" ); document.write( "

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