document.write( "Question 198745: One year ago Walt invested $12000. He invested part of the money at 7% and the rest at 9%. He made a total of $970 in interest. How much was invested at 7%?\r
\n" ); document.write( "\n" ); document.write( "I do not know where to place what number in the formula equation
\n" ); document.write( "ax2 + bx + c = 0
\n" ); document.write( "

Algebra.Com's Answer #149246 by checkley75(3666)\"\" \"About 
You can put this solution on YOUR website!
ax2 + bx + c = 0
\n" ); document.write( "This is not the correct formula for this type of problem.
\n" ); document.write( ".09x+.07(12,000-x)=970 is the correct formula.
\n" ); document.write( ".09x+840-.07x=970
\n" ); document.write( ".02x=970-840
\n" ); document.write( ".02x=130
\n" ); document.write( "x=130/.02
\n" ); document.write( "x=6,500 amount invested @ 9%.
\n" ); document.write( "12,000-6,500=5,500 amount invested @ 7%.
\n" ); document.write( "Proof:
\n" ); document.write( ".09*6,500+.07*5,500=970
\n" ); document.write( "585+385=970
\n" ); document.write( "970=970
\n" ); document.write( "
\n" );