document.write( "Question 198745: One year ago Walt invested $12000. He invested part of the money at 7% and the rest at 9%. He made a total of $970 in interest. How much was invested at 7%?\r
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document.write( "I do not know where to place what number in the formula equation
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document.write( "ax2 + bx + c = 0 \n" );
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Algebra.Com's Answer #149246 by checkley75(3666)![]() ![]() ![]() You can put this solution on YOUR website! ax2 + bx + c = 0 \n" ); document.write( "This is not the correct formula for this type of problem. \n" ); document.write( ".09x+.07(12,000-x)=970 is the correct formula. \n" ); document.write( ".09x+840-.07x=970 \n" ); document.write( ".02x=970-840 \n" ); document.write( ".02x=130 \n" ); document.write( "x=130/.02 \n" ); document.write( "x=6,500 amount invested @ 9%. \n" ); document.write( "12,000-6,500=5,500 amount invested @ 7%. \n" ); document.write( "Proof: \n" ); document.write( ".09*6,500+.07*5,500=970 \n" ); document.write( "585+385=970 \n" ); document.write( "970=970 \n" ); document.write( " |