document.write( "Question 198727: Please HELP!! \r
\n" ); document.write( "\n" ); document.write( "A pelican flying in the air over water drops a crab from a height of 30 feet. The distance the crab is from the water as it falls can be represented by the function h(t)= -16t^2 + 30, where t is time in seconds. To catch the crab as it falls, a gull flies along a path represented by the function
\n" ); document.write( " g(t)= -8t + 15. Can the gull catch the crab before the crab hits the water? \r
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Algebra.Com's Answer #149228 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Simply set the height equations equal to each other and solve for \"t\"\r
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\n" ); document.write( "\n" ); document.write( "\"-16t%5E2+%2B+30=-8t+%2B+15\" Set the two right sides equal to each other.\r
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\n" ); document.write( "\n" ); document.write( "\"-16t%5E2%2B30%2B8t-15=0\" Get all terms to the left side.\r
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\n" ); document.write( "\n" ); document.write( "\"-16t%5E2%2B8t%2B15=0\" Combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "Notice we have a quadratic in the form of \"At%5E2%2BBt%2BC\" where \"A=-16\", \"B=8\", and \"C=15\"\r
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\n" ); document.write( "\n" ); document.write( "Let's use the quadratic formula to solve for \"t\":\r
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\n" ); document.write( "\n" ); document.write( "\"t+=+%28-B+%2B-+sqrt%28+B%5E2-4AC+%29%29%2F%282A%29\" Start with the quadratic formula\r
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\n" ); document.write( "\n" ); document.write( "\"t+=+%28-%288%29+%2B-+sqrt%28+%288%29%5E2-4%28-16%29%2815%29+%29%29%2F%282%28-16%29%29\" Plug in \"A=-16\", \"B=8\", and \"C=15\"\r
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\n" ); document.write( "\n" ); document.write( "\"t+=+%28-8+%2B-+sqrt%28+64-4%28-16%29%2815%29+%29%29%2F%282%28-16%29%29\" Square \"8\" to get \"64\". \r
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\n" ); document.write( "\n" ); document.write( "\"t+=+%28-8+%2B-+sqrt%28+64--960+%29%29%2F%282%28-16%29%29\" Multiply \"4%28-16%29%2815%29\" to get \"-960\"\r
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\n" ); document.write( "\n" ); document.write( "\"t+=+%28-8+%2B-+sqrt%28+64%2B960+%29%29%2F%282%28-16%29%29\" Rewrite \"sqrt%2864--960%29\" as \"sqrt%2864%2B960%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"t+=+%28-8+%2B-+sqrt%28+1024+%29%29%2F%282%28-16%29%29\" Add \"64\" to \"960\" to get \"1024\"\r
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\n" ); document.write( "\n" ); document.write( "\"t+=+%28-8+%2B-+sqrt%28+1024+%29%29%2F%28-32%29\" Multiply \"2\" and \"-16\" to get \"-32\". \r
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\n" ); document.write( "\n" ); document.write( "\"t+=+%28-8+%2B-+32%29%2F%28-32%29\" Take the square root of \"1024\" to get \"32\". \r
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\n" ); document.write( "\n" ); document.write( "\"t+=+%28-8+%2B+32%29%2F%28-32%29\" or \"t+=+%28-8+-+32%29%2F%28-32%29\" Break up the expression. \r
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\n" ); document.write( "\n" ); document.write( "\"t+=+%2824%29%2F%28-32%29\" or \"t+=++%28-40%29%2F%28-32%29\" Combine like terms. \r
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\n" ); document.write( "\n" ); document.write( "\"t+=+-3%2F4\" or \"t+=+5%2F4\" Simplify. \r
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\n" ); document.write( "\n" ); document.write( "So possible the solutions are \"t+=+-3%2F4\" or \"t+=+5%2F4\" \r
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\n" ); document.write( "\n" ); document.write( "Since a negative time doesn't make sense, this means that the only solution is \"t+=+5%2F4\" which is \"t=1.25\"\r
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\n" ); document.write( "\n" ); document.write( "So the pelican will catch the crab in 1.25 seconds. \r
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\n" ); document.write( "\n" ); document.write( "Notice how if we plug in \"t=1.25\" into either equation, we get: \r
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\n" ); document.write( "\n" ); document.write( "\"g%281.25%29=-8%281.25%29%2B15=-10%2B15=5\" which means that the pelican will meet with the crab 5 feet in the air. \r
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\n" ); document.write( "\n" ); document.write( "So the gull will catch the crab before the crab hits the water.
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