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find the equation of the straight line joining A=(4,-2) c=(3,0)show working.\r
\n" ); document.write( "\n" ); document.write( "The formula for the equation to the stline joining two given pts
\n" ); document.write( "The equation of the straight line joining two given points A(x1,y1) and B(x2,y2) is given by
\n" ); document.write( "(y- y1)/(y1- y2) = (x- x1)/(x1- x2)
\n" ); document.write( "Applying the above formula to the stline joining A(4,-2) and C(3,0)
\n" ); document.write( "we have (y-(-2))/[(-2)-0] = (x-4)/(4-3) (where x1=4, y1=-2 and x2=3, y1=0)
\n" ); document.write( "That is (y+2)/(-2) = (x-4)/1
\n" ); document.write( "That is (y+2) X 1 = (-2) X (x-4) (cross multiplication)
\n" ); document.write( "(y+2) = -2x +8
\n" ); document.write( "That is 2x +y +2-8 = 0 (Transposing, change side than change sign)
\n" ); document.write( "2x+ y -6 = 0
\n" ); document.write( "Answer: The required line is 2x + y - 6 = 0
\n" ); document.write( "Verification:
\n" ); document.write( "Testing for A(4,-2) in the answer, (putting x=4, y=-2)
\n" ); document.write( "LHS = 2X4 -2 -6 = 8-8 =0 =RHS
\n" ); document.write( "Testing for C(3,0) in the answer, (putting x=3, y=0)
\n" ); document.write( "LHS = 2X3 +0 -6 = 6-6 =0 =RHS
\n" ); document.write( "Therefore both the given points satisfy the equation that we have got. Hence we are right. \n" ); document.write( "