document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=198631>Question 198631</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solving Word Problems Using Quadratic Equations<BR>\n" );
document.write( "24. A rectangular field measures 15 m by 20 m. A rectangular area is to be fenced in by reducing each dimension by the same amount. The fenced-in area be?<BR>\n" );
document.write( "Thanks@@!!! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #149167 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=149167\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 24. A rectangular field measures 15 m by 20 m. A rectangular area is to be fenced in by reducing each dimension by the same amount. The fenced-in area be?<BR>\n" );
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document.write( "Let x = reduction<BR>\n" );
document.write( "then<BR>\n" );
document.write( "15-x = width<BR>\n" );
document.write( "20-x = length<BR>\n" );
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document.write( "Area = (15-x)(20-x)<BR>\n" );
document.write( "Area = (15-x)(20-x)<BR>\n" );
document.write( "Area = 300-15x-20x-x^2<BR>\n" );
document.write( "Area = 300-35x-x^2<BR>\n" );
document.write( "Area = -x^2-35x+300\r<BR>\n" );
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