document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=198643>Question 198643</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A cruise boat travels 72 miles down stream in two hours and returns upstream in 6 hours. Find the rate of the stream.\r<BR>\n" );
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document.write( "D=RT so R=D/T  72/2=36 72/6=12 36-12=24 (speed of boat on still water?)\r<BR>\n" );
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document.write( "I get lost here.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #149151 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=149151\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A cruise boat travels 72 miles down stream in two hours and returns upstream in 6 hours. Find the rate of the stream. <BR>\n" );
document.write( "D=RT so R=D/T 72/2=36 72/6=12 36-12=24 (speed of boat on still water?) <BR>\n" );
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document.write( "Going downstream, the speed of the stream is added to the speed of the boat.<BR>\n" );
document.write( "Upstream, it's subtracted.<BR>\n" );
document.write( "72 = (b+s)*2<BR>\n" );
document.write( "72 = (b-s)*6<BR>\n" );
document.write( "b+s = 36<BR>\n" );
document.write( "b-s = 12<BR>\n" );
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document.write( "2b = 48<BR>\n" );
document.write( "b = 24 mph (speed of boat)<BR>\n" );
document.write( "s = 12 mph (speed of stream)<BR>\n" );
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