document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=198645>Question 198645</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Joe has a collection of nickels and dimes that is worth $6.80. If the number of dimes were doubled and the number of nickels increased by 6, the value of the coins would be $11.10 How many dimes does he have?\r<BR>\n" );
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document.write( "Nickels = X  <BR>\n" );
document.write( "Dimes = Y  <BR>\n" );
document.write( "X+Y=6.80<BR>\n" );
document.write( "X+6+2Y=$11.10\r<BR>\n" );
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document.write( "-(x+y=6.80) <BR>\n" );
document.write( "-x-y=-6.80  <BR>\n" );
document.write( "x+6+y=11.10 <BR>\n" );
document.write( "6+y=4.30<BR>\n" );
document.write( "y=-1.7\r<BR>\n" );
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document.write( "This is not the answer, but its what I keep going back to.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #149145 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=149145\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> try this ___ X(.05) + Y(.10) = 6.80\r<BR>\n" );
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document.write( "and this ___ (X+6)(.05) + (2Y)(.10) = 11.10 </SPAN>\n" );
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