document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=27468>Question 27468</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two trains, 90 miles apart, start heading toward each other at the same time.  One travels twice as fast as the other.  If they meet 2 hours later, at what average speed is each train traveling? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #14911 by </B><A HREF=/tutors/aboutme.mpl?userid=Paul><B>Paul(988)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Paul><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=14911\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> One train's speed = x<BR>\n" );
document.write( "Other's trian's speed = 2x<BR>\n" );
document.write( "TIme they meet after = 2 hours.\r<BR>\n" );
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document.write( "2(x+2x)=90<BR>\n" );
document.write( "2(3x)=90<BR>\n" );
document.write( "6x=90<BR>\n" );
document.write( "x=15\r<BR>\n" );
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document.write( "2(15)=30.\r<BR>\n" );
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document.write( "Hence, the speed of one train is 15mph and for other its 30mph.<BR>\n" );
document.write( "Paul. </SPAN>\n" );
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