document.write( "Question 198568: Blockbuster is testing a new policy of waiving all late fees on DVD rentals using a sample of 10 randomly chosen customers. (a) At a-.10, does the data show that the man number of monthly rentals has increased? (b) Is the decision close? (c) Are you convinced?\r
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document.write( "Customer No Late Fee Late Fee
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document.write( " 1 14 10
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document.write( " 2 12 7
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document.write( " 3 14 10
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document.write( " 4 13 13
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document.write( " 5 10 9
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document.write( " 6 13 14
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document.write( " 7 12 12
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document.write( " 8 10 7
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document.write( " 9 13 13
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document.write( "10 13 9\r
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document.write( "I can figure out the mean which is 12.4 of no late fee but cannot figure out the rest, can someone please help. Thanks
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Algebra.Com's Answer #149096 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Blockbuster is testing a new policy of waiving all late fees on DVD rentals using a sample of 10 randomly chosen customers. (a) At a-.10, does the data show that the man number of monthly rentals has increased? (b) Is the decision close? (c) Are you convinced? \n" ); document.write( "Customer No Late Fee Late Fee \n" ); document.write( "1 14 10 \n" ); document.write( "2 12 7 \n" ); document.write( "3 14 10 \n" ); document.write( "4 13 13 \n" ); document.write( "5 10 9 \n" ); document.write( "6 13 14 \n" ); document.write( "7 12 12 \n" ); document.write( "8 10 7 \n" ); document.write( "9 13 13 \n" ); document.write( "10 13 9 \n" ); document.write( "----------------- \n" ); document.write( "These data are dependent pairs because each pair measures a \"before\" \n" ); document.write( "and \"after\" for the same person. \n" ); document.write( "--------------------- \n" ); document.write( "Make a list for each data set. \n" ); document.write( "Make a list of the difference (no late fee)-(late fee) \n" ); document.write( "------------ \n" ); document.write( "------------------ \n" ); document.write( "Run a t-test on the difference of the 10 pairs. \n" ); document.write( "mean of the difference = 2 \n" ); document.write( "-------------------------------------- \n" ); document.write( "Ho: u(difference) = 0 \n" ); document.write( "H1: u(difference) > 0 \n" ); document.write( "Decision Rule: Reject Ho if the test statistic is greater than 1.383.. \n" ); document.write( "test statistic: t = 2.8604 \n" ); document.write( "p-value: 0.0094 \n" ); document.write( "----------- \n" ); document.write( "Conclusion: Since the p-value is less than 10%, reject Ho. \n" ); document.write( "The test provides evidence that the mean of the differences \n" ); document.write( "is not zero. \n" ); document.write( "====================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |