document.write( "Question 198550: solve:
\n" ); document.write( "log6(5-2a)-log6(3a)=1
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Algebra.Com's Answer #149062 by stanbon(75887)\"\" \"About 
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solve:
\n" ); document.write( "log6(5-2a)-log6(3a)=1
\n" ); document.write( "------------
\n" ); document.write( "log6[(5-2a)/(3a)] = 1
\n" ); document.write( "(5-2a)/3a = 6^1
\n" ); document.write( "5-2a = 18a
\n" ); document.write( "20a = 5
\n" ); document.write( "a = 1/4
\n" ); document.write( "-----------------
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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