document.write( "Question 198526: Five years from now, A will be 4/5 as old as B; five years ago, he was 2/3 as old then. Find their present ages. \n" ); document.write( "
Algebra.Com's Answer #149058 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Five years from now, A will be 4/5 as old as B; five years ago, \n" ); document.write( " he was 2/3 as old then. \n" ); document.write( " Find their present ages. \n" ); document.write( ": \n" ); document.write( "Write an equation for each statement: \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( "Multiply by 5, to get rid of the denominator, simplify \n" ); document.write( "4(A+5) = 5(B+5) \n" ); document.write( "4A + 20 = 5B + 25 \n" ); document.write( "4A - 5B = -20 + 25 \n" ); document.write( "4A - 5B = 5 \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( "Multiply by 3 \n" ); document.write( "2(A-5) = 3(B-5) \n" ); document.write( "2A - 10 = 3b - 15 \n" ); document.write( "2A - 3B = -15 + 10 \n" ); document.write( "2A - 3B = -5 \n" ); document.write( ": \n" ); document.write( "Multiply the above equation by -2, add to the 1st equation \n" ); document.write( "-4A + 6B = +10 \n" ); document.write( "+4A - 5B = 5 \n" ); document.write( "--------------- \n" ); document.write( "B = 15 yrs is B's age now \n" ); document.write( "then \n" ); document.write( "Use 4A - 5B = 5 to find A \n" ); document.write( "4A - 5(15) - 5 \n" ); document.write( "4A - 75 = 5 \n" ); document.write( "4A = 5 + 75 \n" ); document.write( "4A = 80 \n" ); document.write( "A = \n" ); document.write( "A = 20 yrs is A's age now \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check solutions in the statement \n" ); document.write( "Five years from now, A will be 4/5 as old as B; \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "You can check solutions in the 2nd statement \n" ); document.write( " \n" ); document.write( " |