document.write( "Question 198526: Five years from now, A will be 4/5 as old as B; five years ago, he was 2/3 as old then. Find their present ages. \n" ); document.write( "
Algebra.Com's Answer #149058 by ankor@dixie-net.com(22740)\"\" \"About 
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Five years from now, A will be 4/5 as old as B; five years ago,
\n" ); document.write( " he was 2/3 as old then.
\n" ); document.write( " Find their present ages.
\n" ); document.write( ":
\n" ); document.write( "Write an equation for each statement:
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\n" ); document.write( "\"4%2F5\"(A+5) = (B+5)
\n" ); document.write( "Multiply by 5, to get rid of the denominator, simplify
\n" ); document.write( "4(A+5) = 5(B+5)
\n" ); document.write( "4A + 20 = 5B + 25
\n" ); document.write( "4A - 5B = -20 + 25
\n" ); document.write( "4A - 5B = 5
\n" ); document.write( ":
\n" ); document.write( "\"2%2F3\"(A-5) = (B-5)
\n" ); document.write( "Multiply by 3
\n" ); document.write( "2(A-5) = 3(B-5)
\n" ); document.write( "2A - 10 = 3b - 15
\n" ); document.write( "2A - 3B = -15 + 10
\n" ); document.write( "2A - 3B = -5
\n" ); document.write( ":
\n" ); document.write( "Multiply the above equation by -2, add to the 1st equation
\n" ); document.write( "-4A + 6B = +10
\n" ); document.write( "+4A - 5B = 5
\n" ); document.write( "---------------
\n" ); document.write( "B = 15 yrs is B's age now
\n" ); document.write( "then
\n" ); document.write( "Use 4A - 5B = 5 to find A
\n" ); document.write( "4A - 5(15) - 5
\n" ); document.write( "4A - 75 = 5
\n" ); document.write( "4A = 5 + 75
\n" ); document.write( "4A = 80
\n" ); document.write( "A = \"80%2F4\"
\n" ); document.write( "A = 20 yrs is A's age now
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check solutions in the statement
\n" ); document.write( "Five years from now, A will be 4/5 as old as B;
\n" ); document.write( "\"4%2F5\"(20+5) = (15+5)
\n" ); document.write( ":
\n" ); document.write( "You can check solutions in the 2nd statement
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