document.write( "Question 198509: Al mows lawns at a rate of 30 square feet per minute, Bo mows 40 square feet per minute, and Cy mows 60 square feet per minute. They accept a job that requires that they mow 6060 square feet of lawn. Al begins mowing at 7:00 A.M., but Bo does not begin for another 15 minutes. Cy begins mowing at 7:45, and they finish together. How long did Bo work? \n" ); document.write( "
Algebra.Com's Answer #149033 by josmiceli(19441)\"\" \"About 
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Let \"t\"= Al's time mowing in minutes
\n" ); document.write( "given:
\n" ); document.write( "\"30t+%2B+40%2A%28t+-+15%29+%2B+60%2A%28t+-+45%29+=+6060\"
\n" ); document.write( "\"30t+%2B+40t+-+600+%2B+60t+-+2700+=+6060\"
\n" ); document.write( "\"130t+=+6060+%2B+2700+%2B+600\"
\n" ); document.write( "\"130t+=+9360\"
\n" ); document.write( "\"t+=+72\" min
\n" ); document.write( "Bo worked \"15\" less than Al, so
\n" ); document.write( "\"72+-+15+=+57\"
\n" ); document.write( "Bo worked 57 minutes
\n" ); document.write( "check answer:
\n" ); document.write( "\"30t+%2B+40%2A%28t+-+15%29+%2B+60%2A%28t+-+45%29+=+6060\"
\n" ); document.write( "\"30%2A72+%2B+40%2A57+%2B+60%2A27+=+6060\"
\n" ); document.write( "\"2160+%2B+2280+%2B+1620+=+6060\"
\n" ); document.write( "\"6060+=+6060\"
\n" ); document.write( "OK
\n" ); document.write( "
\n" );