document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=198291>Question 198291</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In the parallelogram, the length AE is 6, the length of BC is 9, and the base DC is 4. Find the area.\r<BR>\n" );
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document.write( "Length 6<BR>\n" );
document.write( "Base 4<BR>\n" );
document.write( "Diagnol length 9\r<BR>\n" );
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document.write( "HELP! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #149018 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=149018\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Length 6<BR>\n" );
document.write( "Base 4<BR>\n" );
document.write( "Diagonal length 9<BR>\n" );
document.write( "What you have is a non-right triangle thus the area equation of the triangle is:<BR>\n" );
document.write( "area=sqrt[s(s-a)(s-b)(s-c)]<BR>\n" );
document.write( "s=(a+b+c)/2<BR>\n" );
document.write( "s=(4+6+9)/2=19/2=9.5<BR>\n" );
document.write( "Because sis not a whole number the sides must be doubled and then divide the answer by 4.<BR>\n" );
document.write( "s=(8+12+18)/2=38/2=19<BR>\n" );
document.write( "area=sqrt[19(19-8)(19-12)(19-18)<BR>\n" );
document.write( "area=sqrt[19*11*15*7*1]<BR>\n" );
document.write( "area=sqrt(21,945)<BR>\n" );
document.write( "area=148.14/4=37.03 ans. for half the parallogram.<BR>\n" );
document.write( "37.03*2=74.06 ans. for the area of the parallogram.<BR>\n" );
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