document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=307>Question 307</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The difference between the measures of two complementary angles is 58 degrees.  What is the measure of the two angles if using two variables (x and y).<BR>\n" );
document.write( "Tricia </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #149 by </B><A HREF=/tutors/aboutme.mpl?userid=prabhjyot><B>prabhjyot(165)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=prabhjyot><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=149\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> complementary angles are the angles which have sun equal to 90<BR>\n" );
document.write( "Let two angles be x and y<BR>\n" );
document.write( "so x+y=90  ----->(1)<BR>\n" );
document.write( "given that difference of the two numbers is 58<BR>\n" );
document.write( "that means x-y=58  ----->(2)<BR>\n" );
document.write( "from equation (2) x=58+y<BR>\n" );
document.write( "now putting the value of x in equation in (1)<BR>\n" );
document.write( "58+y+y=90<BR>\n" );
document.write( "58+2y=90<BR>\n" );
document.write( "2y=90-58<BR>\n" );
document.write( "y=16<BR>\n" );
document.write( "now plug the value of x in either of the two equation  <BR>\n" );
document.write( "we get x=74<BR>\n" );
document.write( "Therefore two angles are x=74 and y=16 </SPAN>\n" );
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