document.write( "Question 198475: Hi!
\n" ); document.write( "Solve the equation 4abs( 3-x) + 3 = 15\r
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Algebra.Com's Answer #148991 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "\"4%2Aabs%283-x%29%2B3=15\" Start with the given equation\r
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\n" ); document.write( "\n" ); document.write( "\"4%2Aabs%283-x%29=12\" Subtract 3 from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"abs%283-x%29=3\" Divide both sides by 4\r
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\n" ); document.write( "\n" ); document.write( "Break up the absolute value (remember, if you have \"abs%28x%29=a\", then \"x=-a\" or \"x=a\")\r
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\n" ); document.write( "\n" ); document.write( "\"3-x=-3\" or \"3-x=3\" Set the expression \"3-x\" equal to the original value 3 and it's opposite -3\r
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\n" ); document.write( "\n" ); document.write( "Now lets focus on the first equation \"3-x=-3\"\r
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\n" ); document.write( "\n" ); document.write( "\"-x=-3-3\"Subtract 3 from both sides\r
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\n" ); document.write( "\n" ); document.write( "\"-x=-6\" Combine like terms on the right side\r
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\n" ); document.write( "\n" ); document.write( "\"x=%28-6%29%2F%28-1%29\" Divide both sides by -1 to isolate x\r
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\n" ); document.write( "\n" ); document.write( "\"x=6\" Divide\r
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\n" ); document.write( "\n" ); document.write( "Now lets focus on the second equation \"3-x=3\"\r
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\n" ); document.write( "\n" ); document.write( "\"-x=3-3\"Subtract 3 from both sides\r
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\n" ); document.write( "\n" ); document.write( "\"-x=0\" Combine like terms on the right side\r
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\n" ); document.write( "\n" ); document.write( "\"x=%280%29%2F%28-1%29\" Divide both sides by -1 to isolate x\r
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\n" ); document.write( "\n" ); document.write( "\"x=0\" Divide\r
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\n" ); document.write( "\n" ); document.write( "So the solutions to \"4%2Aabs%283-x%29%2B3=15\" are:\r
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\n" ); document.write( "\n" ); document.write( "\"x=6\" and \"x=0\"\r
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