document.write( "Question 198446: A man traveling 40 miles finds that by traveling one more mile per \r
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document.write( "hour he would make a journey in 2 hours less time. How many miles \r
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document.write( "per hour did he actually travel? \n" );
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Algebra.Com's Answer #148962 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A man traveling 40 miles finds that by traveling one more mile per \n" ); document.write( "hour he would make a journey in 2 hours less time. \n" ); document.write( " How many miles per hour did he actually travel? \n" ); document.write( ": \n" ); document.write( "Let s = mph he actually traveled \n" ); document.write( ": \n" ); document.write( "Write a time equation: Time = \n" ); document.write( ": \n" ); document.write( "Actual time - faster time = 2 hrs \n" ); document.write( " \n" ); document.write( "Multiply each term by s(s+1); results: \n" ); document.write( "40(s+1) - 40s = 2s(s+1) \n" ); document.write( ": \n" ); document.write( "40s + 40 - 40s = 2s^2 + 2s \n" ); document.write( "Arrange as a quadratic equation, (40s's cancel) \n" ); document.write( "2s^2 + 2s - 40 = 0 \n" ); document.write( "Simplify, divide by 2 \n" ); document.write( "s^2 + s - 20 = 0 \n" ); document.write( "Factors to \n" ); document.write( "(s-4)(s+5) = 0 \n" ); document.write( "The positive solution \n" ); document.write( "s = 4 mph, actual speed \n" ); document.write( "then \n" ); document.write( "5 mph is the faster speed \n" ); document.write( "; \n" ); document.write( "Check solution find the times \n" ); document.write( "40/4 = 10 hrs \n" ); document.write( "40/5 = 8 hrs \n" ); document.write( " |