document.write( "Question 198410: At Ajax Spring Water, a half-liter bottle of soft drink is supposed to contain a mean of 520 ml. The filling process follows a normal distribution with a known process standard deviation of 4 ml.
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document.write( "(a) Which sampling distribution would you use if random samples of 10 bottles are to be weighed? Why?
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document.write( " (b) Set up hypotheses and a two-tailed decision rule for the correct mean using the 5 percent
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document.write( "level of significance.
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document.write( "(c) If a sample of 16 bottles shows a mean fill of 515 ml, does this contradict the hypothesis that the true mean is 520 ml?
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Algebra.Com's Answer #148949 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! At Ajax Spring Water, a half-liter bottle of soft drink is supposed to contain a mean of 520 ml. The filling process follows a normal distribution with a known process standard deviation of 4 ml. \n" ); document.write( "(a) Which sampling distribution would you use if random samples of 10 bottles are to be weighed? Why? \n" ); document.write( "The \"t\" distribution because the samples are small. \n" ); document.write( "-------------------------------------------------------- \n" ); document.write( "(b) Set up hypotheses and a two-tailed decision rule for the correct mean using the 5 percent level of significance.\r \n" ); document.write( "\n" ); document.write( "Ho: u = 520 \n" ); document.write( "Ha: u is not equal to 520 \n" ); document.write( "Reject Ho is the test statistic is less than -2.262 or greater than +2.262\r \n" ); document.write( "\n" ); document.write( "--------------------------------------------------------- \n" ); document.write( " \n" ); document.write( "(c) If a sample of 16 bottles shows a mean fill of 515 ml, does this contradict the hypothesis that the true mean is 520 ml? \n" ); document.write( "Note: You have changed the sample size. \n" ); document.write( "-------------------- \n" ); document.write( "t(515) = (515-520)/[4/Sqrt(16)] = -5 \n" ); document.write( "The p-value for a 2-tail test with t = -5 and df=15 = 2[P(t<-5)]=0.000158 \n" ); document.write( "Since the p-value is less than 5%, reject Ho. \n" ); document.write( "The test does not support the claim that the mean amount is 520 mL. \n" ); document.write( "======================================================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |