document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=198389>Question 198389</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Quadratic Equation<BR>\n" );
document.write( "9. The area of a triangle is 20cm^2, and the altitude is 4cm greater than the base. Find the length of the base, to the nearest millimetre.<BR>\n" );
document.write( "Thanks!!! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #148944 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=148944\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (1/2)ab=A<BR>\n" );
document.write( "a=b+4<BR>\n" );
document.write( "(1/2)b(b+4)=20<BR>\n" );
document.write( "b^2+4b=40<BR>\n" );
document.write( "b^2+4b-40=0<BR>\n" );
document.write( "b^2+4b    =40<BR>\n" );
document.write( "b^2+4b+4=40+4 completing the square.<BR>\n" );
document.write( "(b+2)^2=44<BR>\n" );
document.write( "b+2=+-sqrt(44)<BR>\n" );
document.write( "b=-2+-sqrt(11*4)<BR>\n" );
document.write( "b=-2+-2sqrt(11)<BR>\n" );
document.write( "b=-2+2sqrt(11) cm, b=-2-2sqrt(11) cm<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Ed </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );