document.write( "Question 198200: : xw is an angle bisector angle yxz=9x+38, angle wxy=10x-14, angle xzy=8x. find angle wzx. is xw an altitude? \n" ); document.write( "
Algebra.Com's Answer #148905 by RAY100(1637) ![]() You can put this solution on YOUR website! Bisector leads to 10x -14 = (1/2) (9x+38) \n" ); document.write( ". \n" ); document.write( "20x -28 = 9x +38 \n" ); document.write( ". \n" ); document.write( "11x = 66 \n" ); document.write( ". \n" ); document.write( "x=6 \n" ); document.write( ". \n" ); document.write( "Subst in 8x = 48 = angle xzy \n" ); document.write( ". \n" ); document.write( "for xw to be altitude angle zwx must = 90 degrees, \n" ); document.write( ". \n" ); document.write( "triangle xzw, has angles, xzw =48, and zxw = 46, therefore zwx = 86, and not 90 \n" ); document.write( ". \n" ); document.write( "therefore xw is NOT an altitude \n" ); document.write( " |